Finite Math and Applied Calculus (6th Edition)

Published by Brooks Cole
ISBN 10: 1133607705
ISBN 13: 978-1-13360-770-0

Chapter 10 - Section 10.3 - Limits and Continuity: Algebraic Viewpoint - Exercises - Page 721: 100

Answer

See the explanation below.

Work Step by Step

$f$ can not be a closed function, because closed functions are continuous on their DOMAINS. Since the domain is $\mathbb{R}$, a closed function $f$ is continuous at $x=2$. Thus, the function must not be closed, but rather it must be piecewise. For example, $f(x)=\left\{\begin{array}{lll} -1, & for & x\lt 2\\ +1 & for & x \geq 2 \end{array}\right.$ is defined on all of $\mathbb{R}$, but the one-sided limits at $x=2$ differ, which means that no limit exists there. Thus, $f$ is discontinuous at $x=2$.
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