Answer
True
Work Step by Step
By Fubini's Theorem, we have $\int^{b}_{a}\int^{d}_{c}f(x,y)dydx=\int^{d}_{c}\int^{b}_{a}f(x,y)dxdy$
so $\int^{1}_{0}\int^{2}_{-2}xe^{y}dydx=\int^{2}_{-2}\int^{1}_{0}xe^{y}dxdy$ is correct.
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 9 - Multiveriable Calculus - Chapter Review - Review Exercises - Page 518: 11
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