Answer
False
Work Step by Step
By Funibi's Theorem $\int^{b}_{a}\int^{d}_{c}f(x,y)dydx=\int^{d}_{c}\int^{b}_{c}f(x,y)dxdy$
so $\int^{4}_{2}\int^{5}_{1}(3x+4y)dy dx=\int^{5}_{1}\int^{4}_{2}(3x+4y)dxdy$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 9 - Multiveriable Calculus - Chapter Review - Review Exercises - Page 518: 10
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