Answer
$$\frac{2}{9}x\left( {{{\left( {{x^2} + 15} \right)}^{3/2}} - {{\left( {{x^2} + 12} \right)}^{3/2}}} \right)$$
Work Step by Step
$$\eqalign{
& \int_4^5 {x\sqrt {{x^2} + 3y} dy} \cr
& {\text{the notation }}dy{\text{ indicates integration with respect to }}y,{\text{ so we treat }}y{\text{ as variable and}} \cr
& x{\text{ as a constant}}{\text{. write the integrand as}} \cr
& = \frac{1}{3}x\int_4^5 {{{\left( {{x^2} + 3y} \right)}^{1/2}}\left( 3 \right)dy} \cr
& {\text{using the power rule }} \cr
& = \frac{1}{3}x\left( {\frac{{{{\left( {{x^2} + 3y} \right)}^{3/2}}}}{{3/2}}} \right)_4^5 \cr
& {\text{then}} \cr
& = \frac{2}{9}x\left( {{{\left( {{x^2} + 3y} \right)}^{3/2}}} \right)_4^5 \cr
& {\text{evaluating the limits in the variable }}y \cr
& = \frac{2}{9}x\left( {{{\left( {{x^2} + 3\left( 5 \right)} \right)}^{3/2}} - {{\left( {{x^2} + 3\left( 4 \right)} \right)}^{3/2}}} \right) \cr
& {\text{simplifying}} \cr
& = \frac{2}{9}x\left( {{{\left( {{x^2} + 15} \right)}^{3/2}} - {{\left( {{x^2} + 12} \right)}^{3/2}}} \right) \cr} $$