Answer
a. 10;
b. $\frac{\sqrt 905}{2}$;
c. $10\sqrt 10$;
d. -5.09
Work Step by Step
Since $f(x,y) = \frac{\sqrt 9x+5y}{\log x}$
a. $h(10,2) = \frac{\sqrt 9(10)+5(2)}{\log 10}=10$
b. $h(100,1) = \frac{\sqrt 9(100)+5(1)}{\log 100}=\frac{\sqrt 905}{2}$
c. $h(1000, 0) =\frac{\sqrt 9(1000)+5(0)}{\log 1000}=10\sqrt 10$
d. $h(\frac{1}{10},5) = \frac{\sqrt 9(\frac{1}{10})+5(5)}{\log \frac{1}{10}}\approx -5.09$
