Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 9 - Multiveriable Calculus - 9.1 Functions of Several Variables - 9.1 Exercises - Page 467: 1

Answer

$$f(2,-1)=12,\ f(-4,1)=-6,\ f(-2,-3)=10,\ f(0,8)=-19$$

Work Step by Step

Since $$f(x, y)=2 x-3 y+5$$ Then \begin{align*} f(2,-1)&==2 (2)-3 (-1)+5\\ &=12 \end{align*} and \begin{align*} f(-4,1)&==2 (-4)-3 (1)+5\\ &=-6 \end{align*} \begin{align*} f(-2,-3)&==2 (-2)-3 (-3)+5\\ &=10 \end{align*} \begin{align*} f(0,8)&==2 (0)-3 (8)+5\\ &=-19 \end{align*}
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