Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - Chapter Review - Review Exercises - Page 417: 5

Answer

True

Work Step by Step

\[\begin{align} & \text{The statement is True, an integral is more easily to solve using } \\ & \text{the substitution method with the chain rule, example}\text{.} \\ & \int{\sqrt[3]{{{x}^{2}}+3x}\left( 2x+3 \right)}dx \\ & \text{Is we take }u={{x}^{2}}+3x,\text{ }du=\left( 2x+3 \right)dx \\ & \int{\sqrt[3]{{{x}^{2}}+3x}\left( 2x+3 \right)}dx=\int{\sqrt[3]{u}}du=\int u^{1/3}du \\ \end{align}\]
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