Answer
False
Work Step by Step
\[\begin{align}
& \int{{{x}^{n}}}dx=\frac{{{x}^{n+1}}}{n+1}+C,\text{ where }n\ne -1 \\
& \text{Therefore, the statement is false, if }n=-1 \\
& \int{{{x}^{n}}}dx=\int{{{x}^{-1}}}dx \\
& =\int{\frac{1}{x}}dx=\ln \left| x \right|+C \\
& \text{False} \\
\end{align}\]
