Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 7 - Integration - 7.4 The Fundamental Theorem of Calculus - 7.4 Exercises - Page 395: 1

Answer

$$ - 18$$

Work Step by Step

$$\eqalign{ & \int_{ - 2}^4 {\left( { - 3} \right)} dp \cr & {\text{use the constant multiple rule }}\int k f\left( x \right)dx = k\int {f\left( x \right)dx} \cr & = - 3\int_{ - 2}^4 {dp} \cr & {\text{integrate by using }}\int {dx} = x + C.{\text{ then}} \cr & = - 3\left[ p \right]_{ - 2}^4 \cr & {\text{use fundamental theorem of calculus }}\int_a^b {f\left( x \right)} dx = F\left( b \right) - F\left( a \right).\,\,\,\,\left( {{\text{see page 388}}} \right) \cr & = - 3\left[ {4 - \left( { - 2} \right)} \right] \cr & {\text{simplifying}} \cr & = - 3\left( 6 \right) \cr & = - 18 \cr} $$
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