Answer
$dy=0.1$
Work Step by Step
$y=8-x^{2}+x^{3}$
$y'=-2x+3x^{2}$
$dy=f'(x)dx$
$dy=(-2x+3x^{2})dx$
With x=-1; dx=0.02
$dy=0.1$
Calculus with Applications (10th Edition)
by Lial, Margaret L.; Greenwell, Raymond N.; Ritchey, Nathan P.
Published by
Pearson
ISBN 10:
0321749006
ISBN 13:
978-0-32174-900-0
Chapter 6 - Applications of the Derivative - Chapter Review - Review Exercises - Page 351: 42
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