Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 6 - Applications of the Derivative - Chapter Review - Review Exercises - Page 351: 37


$\frac{dy}{dt}=-12e^{3} \approx -214.026$

Work Step by Step

$y=xe^{3x}$ $\frac{dy}{dt}=(3e^{3x}+3xe^{3x})\frac{dx}{dt}$ $\frac{dy}{dt}=e^{3x}(3+3x)\frac{dx}{dt}$ Now substitute x=1; dx/dt=-2 $\frac{dy}{dt}=-12e^{3} \approx -214.026$
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