Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 6 - Applications of the Derivative - Chapter Review - Review Exercises - Page 351: 36

Answer

$\frac{dy}{dt}=\frac{-2}{9}$

Work Step by Step

$\frac{x^{2}+5y}{x-2y}=2$ $x^{2}+5y=2x-2xy$ $2x\frac{dx}{dt}+5\frac{dy}{dt}=2\frac{dx}{dt}-2x\frac{dy}{dt}-2y\frac{dx}{dt}$ $(5+2x)\frac{dy}{dt}=(2-2x-2y)\frac{dx}{dt}$ Now substitute x=2; y=0; dx/dt=1 $9\frac{dy}{dt}=-2$ $\frac{dy}{dt}=\frac{-2}{9}$
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