Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 6 - Applications of the Derivative - 6.5 Related Rates - 6.5 Exercises - Page 341: 9

Answer

$384$ dollars per month.

Work Step by Step

The cost function is given by, $C=0.2x^2+10,000$ Given, $\frac{dx}{dt}=12$ and $x=80$ We have to find $\frac{dC}{dt}$. Differentiating the cost function with respect to $t$ we get, $\frac{dC}{dt}=(0.2)(2x)\frac{dx}{dt}$ $\hspace{0.7cm}=(0.2)(2\times 80)(12)$ $\hspace{0.7cm}=384$ Therefore the rate of change of cost per month is $384$ dollars per month.
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