Answer
$\frac{dy}{dt}=\frac{555}{71}$
Work Step by Step
$\frac{y^{3}-4x^{2}}{x^{3}+2y}=\frac{44}{31}$
$31y^{3}-124x^{2}=44x^{3}+88y$
$93y^{2} \frac{dy}{dt}-248x\frac{dx}{dt}=132x^2\frac{dx}{dt}+88\frac{dy}{dt}$
$(248x+132x^{2})\frac{dx}{dt}=(93y^{2}-88)\frac{dy}{dt}$
Now substitute x =-3, y = -2, and dx/dt =5 to get
$\frac{dy}{dt}=\frac{555}{71}$