Answer
$\frac{1}{5}$
Work Step by Step
$\frac{x^{2}+y}{x-y}=9$
$x^{2}+y=9x-9y$
$2x\frac{dx}{dt}+\frac{dy}{dt}=9\frac{dx}{dt}-9\frac{dy}{dt}$
$(9-2x)\frac{dx}{dt}=10\frac{dy}{dt}$
Now substitute x =4, y = 2, and dx/dt =2 to get
$\frac{dy}{dt}=\frac{1}{5}$