Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 5 - Graphs and the Derivative - 5.1 Increasing and Decreasing Functions - 5.1 Exercises - Page 261: 52

Answer

The number of people infected will start to decrease after approximately $9$ days.

Work Step by Step

The number of people infected (in hundreds) after $t$ days since the start of the infection, is given by the function : $P(t)=\frac{10ln(0.19t+1)}{0.19t+1}$ The number of people infected will start reducing when $\frac{dP}{dt}<0$ since the function $P(t)$ is decreasing as $\frac{dP}{dt}<0$. i.e. $\frac{10(0.19t+1)\frac{0.19}{(0.19t+1)}-10ln(0.19t+1)0.19}{(0.19t+1)^2}<0$ $=1-\ln(0.19t+1)<0$ $=\ln(0.19t+1)>1$ $=0.19t+1>e$ $=t>\frac{e-1}{0.19}\implies t>9.04 \hspace{0.1cm}\text{days}$ Therefore the number of persons infected will start to reduce after approximately $9 \hspace{0.1cm}\text{days}$.
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