Answer
\[{y^,} = - 15{x^3}{e^{ - 5x}} + 20x{e^{ - 5x}} + 9{x^2}{e^{ - 5x}} - 4{e^{ - 5x}}\]
Work Step by Step
\[\begin{gathered}
y = \,\left( {3{x^3} - 4x} \right){e^{ - 5x}} \hfill \\
Find\,\,the\,\,derivative\,\,using\,\,the\,\,product\,\,rule \hfill \\
{y^,} = \,\left( {3{x^3} - 4x} \right)\,{\left( {{e^{ - 5x}}} \right)^,} + \left( {{e^{ - 5x}}} \right)\left( {3{x^3} - 4x} \right){\,^,} \hfill \\
Use\,\,\,\,\frac{d}{{dx}}\,\,\left[ {{e^{g\,\left( x \right)}}} \right] = {e^{g\,\left( x \right)}}{g^,}\,\left( x \right) \hfill \\
Then \hfill \\
{y^,} = \left( {3{x^3} - 4x} \right)\,\left( { - 5{e^{ - 5x}}} \right) + {e^{ - 5x}}\,\left( {9{x^2} - 4} \right) \hfill \\
Simplify\,\,by\,\,multiplying\, \hfill \\
{y^,} = - 15{x^3}{e^{ - 5x}} + 20x{e^{ - 5x}} + 9{x^2}{e^{ - 5x}} - 4{e^{ - 5x}} \hfill \\
\end{gathered} \]
