Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises: 68

Answer

$f(x)$ is odd.

Work Step by Step

$ f(x)$ is odd if $f(-x)=-f(x)$ $ f(x)$ is even if $f(-x)=f(x)$ ------------- $f(x)=x^{3}+x$ $f(-x)=(-x)^{3}+(-x)=-x^{3}-x=-(x^{3}+x)=-f(x)$ $f(x)$ is odd.
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