Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 2 - Nonlinear Functions - 2.1 Properties of Functions - 2.1 Exercises - Page 55: 42


a) 0 b) $\frac{-45}{4}$ c) f(a)=a^2-a-12 d) $\frac{4}{m^2}-\frac{2}{m}-12$ e) $x=\frac{1\pm\sqrt 53}{2}$

Work Step by Step

$f(x)=(x+3)(x-4)$ $=x^2-x-12$ $a) f(4) =(4)^2-4-12=0$ $b) f(\frac{-1}{2})=(\frac{-1}{2})^2-(\frac{-1}{2})-12=\frac{-45}{4}$ $c) f(a)=a^2-a-12$ $d) f(\frac{2}{m})=(\frac{2}{m})^2-\frac{2}{m}-12=\frac{4}{m^2}-\frac{2}{m}-12$ e) $f(x)=1$ $x^2-x-12=1$ $x^2-x-13=0$ $x=\frac{1\pm\sqrt 53}{2}$
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