## Calculus with Applications (10th Edition)

a) 0 b) $\frac{-45}{4}$ c) f(a)=a^2-a-12 d) $\frac{4}{m^2}-\frac{2}{m}-12$ e) $x=\frac{1\pm\sqrt 53}{2}$
$f(x)=(x+3)(x-4)$ $=x^2-x-12$ $a) f(4) =(4)^2-4-12=0$ $b) f(\frac{-1}{2})=(\frac{-1}{2})^2-(\frac{-1}{2})-12=\frac{-45}{4}$ $c) f(a)=a^2-a-12$ $d) f(\frac{2}{m})=(\frac{2}{m})^2-\frac{2}{m}-12=\frac{4}{m^2}-\frac{2}{m}-12$ e) $f(x)=1$ $x^2-x-12=1$ $x^2-x-13=0$ $x=\frac{1\pm\sqrt 53}{2}$