## Calculus with Applications (10th Edition)

a) $33$ b)$\frac{-1}{4}$ c) $f(a)=3a^2-4a+1$ d) $\frac{12}{m^2}-\frac{8}{m}+1$ e) $x=0$ or $x=\frac{4}{3}$
$f(x)=3x^2-4x+1$ $a) f(4) = 3(4)^2-4(4)+1=33$ $b) f(\frac{-1}{2})=3(\frac{1}{2})^2-4(\frac{1}{2})+1=\frac{-1}{4}$ $c) f(a)=3a^2-4a+1$ $d) f(\frac{2}{m})=3(\frac{2}{m})^2-4(\frac{2}{m})+1=\frac{12}{m^2}-\frac{8}{m}+1$ e) $f(x)=1$ $3x^2-4x+1=1$ $3x^2-4x=0$ $x=0$ or $x=\frac{4}{3}$