Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 12 - Sequences and Series - 12.5 Taylor Series - 12.5 Exercises - Page 647: 2

Answer

$-3+-3x^{2}-3x^{3}-...-x^{n}-...$

Work Step by Step

We are given $f(x)=\frac{-3}{1-x}$ with $a=-3$ for $r$ in $(-1,1)$ The Taylor series for $f(x)=\frac{-3}{1-x}$ is $f(x)=a_{0}+a_{1}x+a_{2}x^{2}+...+a_nx^{n}+...$ $=-3+-3x^{2}-3x^{3}-...-x^{n}-...$
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