## Calculus with Applications (10th Edition)

$45.35\%$
From the normal curve table, the area to the right of $z=1.68$ is $0.9535$ Therefore, the area to the right is $P(0\lt Z \lt 1.68)=0.9535-0.5=0.4535$ The proportion is $0.4535$ or $45.35\%$