Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 11 - Probability and Calculus - 11.3 Special Probability Density Functions - 11.3 Exercises - Page 597: 7

Answer

$49.98\%$

Work Step by Step

From the normal curve table, the area to the right of $z=3.5$ is $0.9998$ Therefore, the area to the right is $P(0\lt Z \lt 1.68)=0.9998-0.5=0.4998$ The proportion is $0.4998$ or $49.98\%$
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