Calculus with Applications (10th Edition)

Published by Pearson
ISBN 10: 0321749006
ISBN 13: 978-0-32174-900-0

Chapter 11 - Probability and Calculus - 11.3 Special Probability Density Functions - 11.3 Exercises - Page 597: 12



Work Step by Step

The proportion is $2\%$ which mean the corresponding area is $0.02$ The z-table gives the result from looking up 2.0 in the left column and 0.05 in the top row. The intersection is $2.05$ Therefore, the area to the left is $z=-2.05$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.