Answer
$\int \frac{x^5+ x - 1}{x^3 +1} dx $ $=$ $\frac{x^3}{3} - ln | x+1| +c$
Work Step by Step
$ \frac{x^5+ x - 1}{x^3 +1} $ $= x^2 + \frac{-1(x^2-x+1)}{x^3 +1}$
$Thus ,$
$\int x^2 +\frac{-1(x^2-x+1)}{x^3 +1} dx $
$=\int x^2 +\frac{-1(x^2-x+1)}{(x +1)(x^2 -x+1) } dx $
$=\int x^2 +\frac{-1}{x +1} dx $
$= \frac{x^3}{3} - ln |x+1| +c$