Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 7 - Review - Exercises - Page 538: 17

Answer

$x\sinh x-\cosh x+C$

Work Step by Step

$\displaystyle \int x\cosh xdx=$ by parts, $\displaystyle \left[\begin{array}{ll} u=x & dv=\cosh xdx\\ du=dx & v=\sinh x \end{array}\right],\quad \int udv=uv-\int vdu$ $=x\displaystyle \sinh x-\int\sinh xdx$ $=x\sinh x-\cosh x+C$
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