Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.3 - Volumes by Cylindrical Shells - 6.3 Exercises - Page 454: 34

Answer

$\displaystyle{V=21.253}$

Work Step by Step

$\displaystyle{V=\int_{0.906}^{2.715}(2\pi x)\left(e^{\sin x}-\left(x^2-4x+5\right)\right)\ dx}\\ \displaystyle{V=2\pi\int_{0.906}^{2.715}xe^{\sin x}-x^3+4x^2-5x\ dx}\\ \displaystyle{V=21.253}$
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