Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 6 - Section 6.3 - Volumes by Cylindrical Shells - 6.3 Exercises - Page 454: 33

Answer

$\displaystyle{V=14.450}$

Work Step by Step

$\displaystyle{V=\int_{0}^{2.175}(2\pi x)\left(\frac{x}{x^{2}+1}-\left(x^{2}-2x\right)\right)\ dx}\\ \displaystyle{V=2\pi\int_{0}^{2.175}\frac{x^2}{x^{2}+1}-x^{3}+2x^2\ dx}\\ \displaystyle{V=14.450}$
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