## Calculus: Early Transcendentals 8th Edition

$\frac{1}{5}$
Since $y = \sqrt[4] x$, then $x = y^4$ We can evaluate the integral to find the area of the region: $\int_{0}^{1}y^4~dy$ $=\frac{y^5}{5}~\vert_{0}^{1}$ $=(\frac{1^5}{5})-(\frac{0^5}{5})$ $=\frac{1}{5}$