Answer
$1.360$
Work Step by Step
The graph intersects the $x$-axis at $x_1\approx -0.86$ and $x_2\approx 0.42$.
$\int_{-0.86}^{0.42}(1-2x-5x^4) dx=(x-x^2-x^5)_{-0.86}^{0.42}$
$=(0.42-0.42^2-0.42^5)-(-0.86-(-0.86)^2-(-0.86)^5)$
$\approx 1.360$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 5 - Section 5.4 - Indefinite Integrals and the Net Change Theorem - 5.4 Exercises - Page 409: 47
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