Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 390: 48



Work Step by Step

$\int_{a}^{c}f(x)dx=\int_{a}^{b}f(x)dx+\int_{b}^{c}f(x)dx$ So $\int_{2}^{4}f(x)dx+\int_{4}^{8}f(x)dx=\int_{2}^{8}f(x)dx$ $5.9+\int_{4}^{8}f(x)dx=7.3$ $\int_{4}^{8}f(x)dx=1.4$
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