Calculus: Early Transcendentals 8th Edition

$\int_{a}^{c}f(x)dx=\int_{a}^{b}f(x)dx+\int_{b}^{c}f(x)dx$ So $\int_{2}^{4}f(x)dx+\int_{4}^{8}f(x)dx=\int_{2}^{8}f(x)dx$ $5.9+\int_{4}^{8}f(x)dx=7.3$ $\int_{4}^{8}f(x)dx=1.4$