Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 390: 35



Work Step by Step

$\int$(1-x) from -1 to 2: Find the integral of each part of f(x) using the formula $\int x^{n} = 1/(n+1) x^{n+1}$: $\int 1$=1x $\int x=x^{2}/2$ Therefore $\int (1-x) = (x-x^{2}/2)$ To find the area from -1 to 2, find f(2)-f(-1), with f(x) being the newly found integral $(2-2^{2}/2)-(-1-1^{2}/2)$ =3/2
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