## Calculus: Early Transcendentals 8th Edition

$\int$(1-x) from -1 to 2: Find the integral of each part of f(x) using the formula $\int x^{n} = 1/(n+1) x^{n+1}$: $\int 1$=1x $\int x=x^{2}/2$ Therefore $\int (1-x) = (x-x^{2}/2)$ To find the area from -1 to 2, find f(2)-f(-1), with f(x) being the newly found integral $(2-2^{2}/2)-(-1-1^{2}/2)$ =3/2