Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Section 5.2 - The Definite Integral - 5.2 Exercises - Page 390: 41

Answer

$\int_{1}^{1} \sqrt{1+x^4}~dx = 0$

Work Step by Step

Note that the interval $1 \leq x \leq 1$ has a width of zero. If we interpret the integral as the area under the graph, then the area must be zero since the width of the interval is zero. Therefore: $\int_{1}^{1} \sqrt{1+x^4}~dx = 0$
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