Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Review - Exercises - Page 423: 60

Answer

Using the Midpoint Rule, we can estimate that the runner covered a distance of 45.23 meters during those 5 seconds.

Work Step by Step

We can choose five subintervals of the interval $[0,5]$ $\Delta t = \frac{b-a}{n} = \frac{5-0}{5} = 1$ We can find the midpoint of each subinterval: $t_1 = 0.5$ $t_2 = 1.5$ $t_3 =2.5$ $t_4 = 3.5$ $t_5 = 4.5$ We can find an estimate for the distance $D$: $D = \int_{0}^{5}~v(t)~dt \approx \sum_{i=1}^{5} v(t_i)~\Delta t$ $= (4.67+8.86+10.22+10.67+10.81)~(1)$ $= 45.23$ Using the Midpoint Rule, we can estimate that the runner covered a distance of 45.23 meters during those 5 seconds.
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