Answer
$\int \frac{e^{\sqrt{x}}}{\sqrt{x}}~dx = 2e^{\sqrt{x}}+C$
Work Step by Step
$\int \frac{e^{\sqrt{x}}}{\sqrt{x}}~dx$
Let $u = \sqrt{x}$
$\frac{du}{dx} = \frac{1}{2\sqrt{x}}$
$dx = 2\sqrt{x}~du$
$\int (\frac{e^u}{\sqrt{x}})~(2\sqrt{x}~du)$
$=\int 2e^u~du$
$=2e^u+C$
$=2e^{\sqrt{x}}+C$