Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Review - Exercises - Page 423: 31

Answer

$\int \frac{e^{\sqrt{x}}}{\sqrt{x}}~dx = 2e^{\sqrt{x}}+C$

Work Step by Step

$\int \frac{e^{\sqrt{x}}}{\sqrt{x}}~dx$ Let $u = \sqrt{x}$ $\frac{du}{dx} = \frac{1}{2\sqrt{x}}$ $dx = 2\sqrt{x}~du$ $\int (\frac{e^u}{\sqrt{x}})~(2\sqrt{x}~du)$ $=\int 2e^u~du$ $=2e^u+C$ $=2e^{\sqrt{x}}+C$
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