Answer
$\int \frac{sin(ln~x)}{x}~dx = -cos(ln~x)+C$
Work Step by Step
$\int \frac{sin(ln~x)}{x}~dx$
Let $u = ln~x$
$\frac{du}{dx} = \frac{1}{x}$
$dx = x~du$
$\int (\frac{sin~u}{x})~(x~du)$
$=\int sin~u~du$
$= -cos~u+C$
$= -cos(ln~x)+C$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 5 - Review - Exercises - Page 423: 32
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