Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 5 - Review - Exercises - Page 423: 32


$\int \frac{sin(ln~x)}{x}~dx = -cos(ln~x)+C$

Work Step by Step

$\int \frac{sin(ln~x)}{x}~dx$ Let $u = ln~x$ $\frac{du}{dx} = \frac{1}{x}$ $dx = x~du$ $\int (\frac{sin~u}{x})~(x~du)$ $=\int sin~u~du$ $= -cos~u+C$ $= -cos(ln~x)+C$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.