## Calculus: Early Transcendentals 8th Edition

$y'=2x^{2}\cosh(x^{2})+\sinh(x^{2})$
$y=x\sinh(x^{2})$ Start the differentiation process by using the product rule: $y'=x[\sinh(x^{2})]'+(x)'\sinh(x^{2})=...$ Use the chain rule to evaluate the indicated derivatives: $...=x(x^{2})'\cosh(x^{2})+\sinh(x^{2})=...$ $...=(x)(2x)\cosh(x^{2})+\sinh(x^{2})=...$ $...=2x^{2}\cosh(x^{2})+\sinh(x^{2})$