Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 3 - Review - Exercises - Page 267: 45



Work Step by Step

$y=\ln(\cosh3x)$ Start the differentiation process by using the chain rule: $y'=\dfrac{(\cosh3x)'}{\cosh3x}=...$ Apply the chain rule one more time to evaluate the derivative indicated in the numerator and simplify: $...=\dfrac{(3x)'\sinh3x}{\cosh3x}=\dfrac{3\sinh3x}{\cosh3x}=3\tanh3x$
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