Answer
The domain is $(-5,5)$
$g(0) = 1$
$g'(0) = 1$
$g'(-2) = 0$
$\lim\limits_{x \to -5^+}g(x) = \infty$
$\lim\limits_{x \to 5^-}g(x) = 3$
Work Step by Step
The domain is $(-5,5)$
$g(0) = 1$
$g'(0) = 1$
The slope at $~~x=0~~$ is $~~1$
$g'(-2) = 0$
The slope at $~~x=-2~~$ is $~~0$
$\lim\limits_{x \to -5^+}g(x) = \infty$
As $x$ approaches $-5$ from the right, the value of the function becomes larger magnitude positive numbers.
$\lim\limits_{x \to 5^-}g(x) = 3$
As $x$ approaches $5$ from the left, the value of the function gets closer and closer to $3$
