Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 2 - Section 2.7 - Derivatives and Rates of Change - 2.7 Exercises - Page 149: 24

Answer

$g(0) = g(2) = g(4) = 0$ $g'(1) = g'(3) = 0$ $g'(0) = g'(4) = 1$ $g'(2) = -1$ $\lim\limits_{x \to \infty}g(x) = \infty$ $\lim\limits_{x \to -\infty}g(x) = -\infty$

Work Step by Step

$g(0) = g(2) = g(4) = 0$ $g'(1) = g'(3) = 0$ The slope at $~~x=1~~$ and $~~x=3~~$ is $~~0$ $g'(0) = g'(4) = 1$ The slope at $~~x=0~~$ and $~~x=4~~$ is $~~1$ $g'(2) = -1$ The slope at $~~x=2~~$ is $~~-1$ $\lim\limits_{x \to \infty}g(x) = \infty$ $\lim\limits_{x \to -\infty}g(x) = -\infty$
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