Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 16 - Section 16.1 - Vector Fields - 16.1 Exercise - Page 1074: 32

Answer

Plot $I$

Work Step by Step

The level sets of $f$ are circles, so the vector filed must be perpendicular to circles, leaving just $I$ and $III$ as possible plots. Noting that the vectors of the gradient vector filed, $\frac{cos(x^{2}+y^{2})}{\sqrt {x^{2}+y^{2}}}\lt x,y\gt$ , it can be seen that the field point towards the origin as well as away. Hence, the correct plot must be $I$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.