Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 16 - Section 16.1 - Vector Fields - 16.1 Exercise - Page 1074: 29

Answer

$III$

Work Step by Step

The level sets of $f$ are circles, so the vector filed must be perpendicular to circles, leaving just $I$ and $III$ as possible plots. Explicitly calculating the gradient vector filed, $2(x,y)$ it can be seen that the field diverges from the origin, so the correct plot must be $III$.
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