Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 16 - Section 16.1 - Vector Fields - 16.1 Exercise - Page 1074: 18

Answer

Graph $II$

Work Step by Step

Graph $II$ matches to $F(x,y,z)=xi+yj+zk$ because all of the vectors equidistant from the origin have the same magnitude and length. All vectors should point away from the origin.
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