Answer
$\frac{110}{3}$
Work Step by Step
$\int_Cxydx+y^2dy+yzdz=\int_0^1(2t+1)(4t)(2dt)+(4t)^2(4dt)+(4t)(3t-1)(3dt)$
$=[\frac{116t^3}{3}-2t^2]_0^1$
$=\frac{110}{3}$
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