Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 16 - Review - Exercises - Page 1149: 21

Answer

$\int_Cf(x) dx+g(y) dy=0$

Work Step by Step

We need to show that $\int_Cf(x) dx+g(y) dy=0$ Here, $f$ and $g$ are differentiable functions and $C$ is any piece-wise smooth simple closed plane curve. Green's Theorem states that $\int_C Adx+B dy=\iint_D (\dfrac{\partial B}{\partial x}-\dfrac{\partial A}{\partial y})dA$ Here, $D$ is the region enclosed inside the counter-clockwise oriented loop $C$. Here, we have $\int_Cf(x) dx+g(y) dy=\iint_D (\dfrac{\partial g(y)}{\partial x}-\dfrac{\partial f(x)}{\partial y})dA$ Thus, $\int_Cf(x) dx+g(y) dy=0$ Hence, the result has been proved.
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