Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Section 15.9 - Change of Variables in Multiple Integrals - 15.9 Exercise - Page 1060: 8

Answer

The region is bounded by $y=1+x^2$ and the line $x=1$.

Work Step by Step

In order to get the values of $u$ and $v$ we will need to solve the given two equations. we have $y=u(1+v^2) \implies u=\dfrac{y}{1+x^2}$ and $v=x$ As we are given that $0 \leq u \leq 1$ and $0 \leq v \leq 1$ Thus, we can write $0 \leq \dfrac{y}{1+x^2} \leq 1$ and $0 \leq x \leq 1$ This gives: $0 \leq y \leq 1+x^2$ and $0 \leq x \leq 1$ Hence, the region is bounded by $y=1+x^2$ and the line $x=1$.
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