Calculus: Early Transcendentals 8th Edition

Published by Cengage Learning
ISBN 10: 1285741552
ISBN 13: 978-1-28574-155-0

Chapter 15 - Section 15.9 - Change of Variables in Multiple Integrals - 15.9 Exercise - Page 1060: 2

Answer

$4u^2v+uv^2$

Work Step by Step

Here, we have $\dfrac{\partial x}{\partial u}=2u+v$ and $\dfrac{\partial x}{\partial v}=u$ Also, $\dfrac{\partial y}{\partial u}=v^2$ and $\dfrac{\partial y}{\partial v}=2uv$ Now, $Jacobian =\begin{vmatrix} \dfrac{\partial x}{\partial u}&\dfrac{\partial x}{\partial v}\\\dfrac{\partial y}{\partial u}&\dfrac{\partial y}{\partial v}\end{vmatrix}=\begin{vmatrix} 2u+v&u\\v^2&2uv\end{vmatrix}=4u^2v+2uv^2-uv^2=4u^2v+uv^2$
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