Answer
222
Work Step by Step
Evaluate the integral with respect to dy first:
$\int [3x^2y^2-2xy]dx$ with y limits from 0 to 2
$=\int(12x^2-4x)dx$
Evaluate the integral with respect to dx:
$=4x^3-2x^2$ with x limits from 1 to 4
$=256-32-4+2=222$
Calculus: Early Transcendentals 8th Edition
by Stewart, James
Published by
Cengage Learning
ISBN 10:
1285741552
ISBN 13:
978-1-28574-155-0
Chapter 15 - Section 15.1 - Double Integrals over Rectangles - 15.1 Exercise - Page 999: 15
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