Answer
24
Work Step by Step
Set up the integral with limits for x from 0 to 2 and y from 0 to 4:
$\int\int(2x+1) dydx$
Integrate with respect to dy first:
$\int[2xy+y] dx$ with limits for y from 0 to 4
$=\int8x+4 dx$
Integrate with respect to dx:
$4x^2+4x$ evaluated with limits for x from 0 to 2
$=16+8-0=24$
