Answer
$\int x+3x^2y^2dx=2+8y^2$
$\int x+3x^2y^2dy=3x+27x^2$
Work Step by Step
Evaluate the first integral:
$\int x+3x^2y^2dx$ with limits of x from 0 to 2
$=1/2\times x^2 +x^3y^2$ with limits of x from 0 to 2
$=2+8y^2$
Evaluate the second integral:
$\int x+3x^2y^2dy$ with limits of y from 0 to 3
$=xy+x^2y^3$ with limits of y from 0 to 3
$=3x+27x^2$
